A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear a frequency of 65 Hz. What is the frequency of the sound emitted by the horn? The speed of sound in air is 343 m/s.

Respuesta :

Answer:

70 Hz

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr)/(c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away. Β 

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

When the car is approaching you:

fr = 76 Hz

vr = 0 m/s

When the car is moving away from you:

fr = 65 Hz

vr = 0 m/s

c, vs, and fs are constant.

We can write two equations:

76 = fs c / (c βˆ’ vs)

65 = fs c / (c + vs)

If we divide the two equations:

76/65 = [fs c / (c βˆ’ vs)] / [fs c / (c + vs)]

76/65 = [fs c / (c βˆ’ vs)] Γ— [(c + vs) / (fs c)]

76/65 = (c + vs) / (c βˆ’ vs)

76 (c βˆ’ vs) = 65 (c + vs)

76c βˆ’ 76vs = 65c + 65vs

11c = 141vs

vs = 11/141 c

Substitute into either equation to find fs.

65 = fs c / (c + 11/141 c)

65 = fs c / (152/141 c)

65 = 141/152 fs

fs = 70 Hz