Explanation:
The given data is as follows.
   [tex]P_{1}[/tex] = 1 atm,      [tex]P_{2}[/tex] = 2 atm
   [tex]V_{1}[/tex] = 250 ml,     [tex]V_{2}[/tex] = 500 ml
Total volume = [tex]V_{1} + V_{2}[/tex] = 750 ml
Therefore, total pressure will be as follows.
      [tex]P_{total} V_{total} = P_{1}V_{1} + P_{2}V_{2}[/tex]
    [tex]P_{total} = \frac{P_{1}V_{1} + P_{2}V_{2}}{V_{total}}[/tex]
         = [tex]\frac{1 atm \times 250 ml + 2 atm \times 500 ml}{750 ml}[/tex]
        = 1.66 atm
Thus, we can conclude that total pressure of the given mixture is 1.66 atm.
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