Nalzerz Nalzerz

04-04-2020
Mathematics

contestada

Find the sum and write it in standard form
(6x^3+3x^2+3)+(2x^3−5x+1)

Respuesta :

Hrishii Hrishii

04-04-2020

Answer:

[tex] 8 {x}^{3} + 3 {x}^{2} - 5x + 4[/tex]

Step-by-step explanation:

[tex](6 {x}^{3} + 3 {x}^{2} + 3) + (2 {x}^{3} - 5x + 1) \\ = 6 {x}^{3} + 2 {x}^{3} + 3 {x}^{2} - 5x + 3 + 1 \\ = 8 {x}^{3} + 3 {x}^{2} - 5x + 4[/tex]

Answer Link

Otras preguntas

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

find the circumference of a circle whose radius is 15.4cm

find the circumference of a circle whose radius is 15.4cm

find the circumference of a circle whose radius is 15.4cm

find the circumference of a circle whose radius is 15.4cm

What value of x makes the equation true ? 4(2x-4)=16

find the circumference of a circle whose radius is 15.4cm