Gaseous indium dihydride is formed from the elements at elevated temperature:

In(g)+H2(g)⇌InH2(g),Kp=1.48 at 973 K

The partial pressures measured in a reaction vessel are

PIn =0.0540atm
PH2= 0.0250atm
PInH2 =0.0780atm

Calculate Qp and give equal partial pressure for In, H2, and InH2.

Respuesta :

Answer:

The reaction given is:

In (g) + H₂ (g) ⇔ InH₂ (g), the Kp is 1.48 at 973 K.

The partial pressures measured in the reaction vessel is Partial pressure of In is 0.0540 atm, partial pressure of Hâ‚‚ is 0.0250 atm, and the partial pressure of InHâ‚‚ is 0.0780 atm. By using the table given in the attachment below, the value of PInHâ‚‚ is (0.078-x), PIn is (0.054 + x), and the value of PH2 is (0.025 + x).

Kp = PInHâ‚‚/PIn Ă— PHâ‚‚ = (0.078 - x) / (0.054 +x) (0.025 + x)

1.48 = (0.078 - x) / (0.054 +x) (0.025 + x)

x = 0.06689

Now the partial pressures of In, Hâ‚‚ and InHâ‚‚ will be,

PHâ‚‚ = 0.025 + x = 0.025 + 0.0668 = 0.0918 atm

PIn = 0.054 + 0.0668 = 0.1208 atm

PInHâ‚‚ = 0.078 - 0.0668 = 0.0112 atm

Now the Qp or the reaction quotient will be,

Qp = (0.078) / (0.054) (0.025) = 57.78.

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