x = 5i x =-5i
Step-by-step explanation:
x^2+25=0
Rewriting
x^2 - (-25)=0
Writing as the difference of squares
a^2 - b^2= (a-b) (a+b)
where a = x and b = (sqrt(-25)) =±5i
( x-5i) ( x+5i) =0
Using the zero product property
x-5i =0 x+5i =0
Answer:
x = 5i
x = -5i
x² + 25 = 0
x² = 0 - 25
x² = -25
x = √-25
