The maximum temperature : a. 745 K
Given
Gas at 25°C(298 K) and at a pressure of 0.800 atm
Final pressure = 2 atm
Required
Final temperature
Solution
Gay Lussac's Law Ā
When the volume is not changed, the gas pressure in the vessel is proportional to its absolute temperature Ā
[tex]\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
Input the value :
Tā=(PāTā)/Pā
Tā=(2 atm x 298 K)/0.8 atm
Tā = 745 K = 472 °C