The equation of the line that passes through the point (-4 , 3) with slope β2 is:
y = β2x β 5
Given the points are (β4 , β3) and (4 , 1)
The gradient of the line through the points' locations (xβ , yβ) and (xβ , yβ) is: Β yβ β yβ/xβ β xβ
Substitute the given points in the above formula:
=1 β(β3)/4 β (β4)
=4/8
=1/2
If the product of the slopes of two perpendicular lines is -1, then the slope of the perpendicular line is β1/1/2 = β2
Therefore the line that passes through the point (-4 , 3) with slope β2 has equation:
y β 3 = β2(x β 4)
y = β2x β 8 β 3
y = β2x β 5
Hence we get the expression as y = β2x β 5
Learn more about "intercept forms" here-
brainly.com/question/6202710
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