Respuesta :

PHDFlopper
First, we must solve for the radius of the sphere:
V=[tex] \frac{4}{3} [/tex][tex] \pi [/tex][tex] r^{3} [/tex]
r=(3[tex] \frac{V}{4 \pi } [/tex])[tex] ^{ \frac{1}{3} } [/tex]
r=(3*[tex] \frac{900}{4 \pi } [/tex])[tex] ^{ \frac{1}{3} } [/tex]
r≈5.99

Second, we must solve for surface area:
A=4[tex] \pi [/tex][tex] r^{2} [/tex]
A=4*[tex] \pi [/tex]*[tex] 5.99^{2} [/tex]
A≈450.88 [tex] in^{2} [/tex]

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