Answer:
Here, hope it helps :)
Step-by-step explanation:
To find the corresponding value of y at x = 3, we need to plug in x = 3 into the equations of the rocket's path and the missile's path.For the rocket's path:
y1 = β(25 - x^2)
y1 = β(25 - 3^2)
y1 = β(25 - 9)
y1 = β16
y1 = 4So, at x = 3, the rocket's path intersects the y-axis at y1 = 4.For the missile's path:
y2 = 3/2 βx
y2 = 3/2 β3
y2 = 3/2 * β3
y2 = 3/2 * β3
y2 = 3/2 * 1.732 (approximating β3 to 1.732)
y2 = 2.598So, at x = 3, the missile's path intersects the y-axis at y2 = 2.598.
Therefore, the corresponding value of y at x = 3 is y1 = 4 for the rocket's path and y2 = 2.598 for the missile's path.