snailtrail
contestada

Write the equation of the line that passes through the points (2,-6) and (-2,-4).
For the slope, I got -1/2
But I am unsure on how to write the equation.
I know I use the formula y - y1 = m(x-x1)
But I think I am doing something wrong.

Respuesta :

slope = (-4-(-6) / Β (-2-2) Β = 2/-4 = -1/2 Β  You are correct.

Now plug in the point ( 2 , -6) Β into the formally you mentioned above:-

y - (-6) = (-1/2)(x - 2)

y + 6 Β = (-1/2)(x - 2)

to get rid of the fraction you can multiply through by Β 2:-

2y + 12 = -1(x - 2)

2y + 12 = -x + 2

in standard form the equation isΒ 

x + 2y = -10